If you need a fresh copy, you can simply download this file:
1DMotion_PostLab.pdf
We use software and hardware developed by ## MOVIESPlease note: If the movie is too small,please watch via youtube using the YOUTUBE button on bottom right of each video. And, some videos have much higher quality. Find the HD version using the gear icon. 1D Motion: Part 1, Motion Sensor 1D Motion: Part 2, Calibration Theory 1D Motion: Part 3, Calibration 1D Motion: Part 4, About Data Studio 1D Motion: Part 5, About Data Studio 2 Here is a video helping with the concepts of the PostLab. watch in full screen and hd, if available. |

Need help asnwering question 5 on the postlab, i tried both ways method it doenst seem to be the correct asnwer. | Le, Quoc Tue. 04, Mar 2008, 00:10 qle3@msudenver.edu |

Question 3 states "this data forms a continuous, straight line." Therefore, what can you infer about the position data between those time values? What does question 5 state? In light of that, what can you infer about the velocity data between the time values. | Douglas Tue. 04, Mar 2008, 13:20 |

I am uncertain how to include superscripts in my equations in Data Studio. Also, I am unsure of how to insert Pi. Thanks! | Anonymous Wed. 25, Feb 2009, 14:31 |

Bummer, DataStudio cannot insert any type of special formatting. Just use pi and x_o. | Douglas Wed. 25, Feb 2009, 15:06 |

On the post-lab for graph number 1. Do I have to find two diffrent equations or do I just find the slope for the data after the verticle line? | Trengove, Tyler Wed. 17, Feb 2010, 20:56 tnasty001@gmail.com |

The Collision needs to be described with a piecewise function. The first part describes what happens from 0 to 2 seconds. The second part describes what happens from 2 to 8 seconds. Both are of the form: x(t) = x _{o} + v t; where x_{o} and v are constants with appropriate units. Please note: x is in meters, t is in seconds. | Douglas Thu. 18, Feb 2010, 07:49 |

I am not able to open a file that was done in DataSudio. I have tried to install my CD that I received but my computer will not let me. Apparently there is some sort of error. The lab was 1D motion and we need to complete the lab for tomorrow. | Thomas, Rebecca Tue. 23, Feb 2010, 13:19 rthoma60@msudenver.edu |

I don't have enough information from your posting to offer much assistance. The Pasco Website has a tech note to help with installing DataStudio on Windows Vista. I have successfully installed it on Vista with 64 bit using these tech notes very carefully. Tech Note 583 You may, however, evaluate the data that appears in your lab manual using that paper from your lab manual and a pencil. Answer the questions and write out the equations using the model line that appears on the paper. I have included two graphics that you might not see in this email, but if you visit the 1DMotion Web page, they will appear in the Q&A. The Algebra based students do NOT need to write equations for the SHM. The Calculus based students do need to write equations for the SHM. | Douglas Tue. 23, Feb 2010, 14:52 |

Dear Doug, In lab on question 6 dealing with the sine wave, how do we calculate the frequency? Specifically, how do we use the information provided in the A,B,C,D, values to find frequency? Also, do we use these same values to find a and v as we did in problem 5? Thank you. | Jaramillo, Joshua Wed. 22, Sep 2010, 19:51 jaramillo.joshua@gmail.com |

Joshua, You don't need to answer questions about the functions for the sine wave problems (writeup and postlab.) These questions are best answered by Calculus students. Anyhow, to answer your question, Frequency is the inverse of Period. Period is measured in seconds/cycle. Frequency is measured in cycles per second. Look at the web version of this Q&A to see a graphic. | Douglas Thu. 23, Sep 2010, 15:44 |

Hi Douglas, On the post-lab question #3 with the simple harmonic motion graph, it gives us the equation y=0.4*cos(2pi*1/3*x)+1.2. I was wondering what the units were for the numbers. Thanks! | Vue, Douang Sun. 20, Feb 2011, 15:28 douang.vue@email.ucdenver.edu |

Good Question :) y=0.4*cos(2pi*1/3*x)+1.2 This is the equation of motion represented by the plot on the worksheet. y represents position [m] along the track. x represents time [s]. Rewriting we get: x [m] (t) = 0.4 * cos(2pi * 1/3 * time[s] ) + 1.2 Now, what about the units for all the coefficients and constants? The general form for this equation is: x [m] (t) = Amplitude * cos(2pi * 1/Period * time[s] ) + Amplitude_Offset Amplitude is measured in meters and is the distance of the oscillation peak as measured from the equilibrium position (equilibrium is the effective zero point of the oscillation which equals the mean value of many oscillations.) Period is measured in seconds and is the time it takes for one complete cycle. Amplitude_Offset is measured in meters and it is the offset of the equilibrium from position equals 0 [m]. | Douglas Mon. 21, Feb 2011, 09:51 |

Hi Douglas, On the postlab question #3 with the simple harmonic motion graph, using the equation y=0.4*cos(2pi*1/3*x)+1.2, what equation do I use to find out the velocity and acceleration? Thanks! | Anonymous Fri. 23, Sep 2011, 09:09 |

For College Physics: You do not need to find the equations for v and a, simply draw the velocity and acceleration graphs. 1) Find where velocity is zero and plot those first. 2) Find the positive and negative peaks in velocity secondly. Then draw the curve. For General Physics (Calculus Based): Draw the graphs and find the equations. To find the equations of motion take the first and second derivatives of the position equation. It helps to first translate y=... into x(t). y=0.4*cos(2pi*1/3*x)+1.2 x(t) = Amplitude cos( 2 π frequency time ) + Vertical Shift in data. x(t) = 0.4 [m] cos( 2 π 1/3 [1/s] time [s] ) + 1.2 [m] When taking the derivative, don't forget to differentiate the argument of cosine and create a product with the amplitude. Notice [m/s] becomes the amplitude's unit from the first derivative. | Douglas Sun. 25, Sep 2011, 16:18 |

Hi Douglas, I have a question on the "Falling Down" graph on the post lab. I understand that that the general format for x(t) is At^2 + Bt + C, but when it comes to plotting the respective velocity and acceleration graphs, is that same equation to be used with values applied to velocity/acceleration? And if so, can you give me an example? Thanks! | Anonymous Sun. 25, Sep 2011, 15:54 |

y = A x^{2} + B x + C (Let's start by translating this into a physics equation.)x(t) = 1/2 a t ^{2} + v_{o} t + x_{o}From either Kinematics (motion with constant acceleration) or from taking the first time derivative: v(t) = a t + v _{o}Using same method: a = acceleration (constant) You can find a, v _{o}, and x_{o} from the coefficients of the quadratic fit information. (Be careful to notice [ 1/2 a = A; a = 2A] ) Having these decimal values in combination with the above equations will allow you to create plots of both v and a and add basic scale values to the axes of x, v, and a. | Douglas Sun. 25, Sep 2011, 16:28 |

Hello Doug, Quick question, on the write up for 1Dmotion Lab, do you want the physics equation or can we simply write x(t), v(t), a(t) equations with the appropriate units in square brackets? | Anonymous Tue. 27, Sep 2011, 18:10 |

x(t) = 1.9[m] + 0.35[m/s] t v(t) = 0.35 [m/s] a(t) = 0 [m/s/s] That is a sample of what you need for the PostLab. | Douglas Wed. 28, Sep 2011, 09:03 |

For the post lab how do you graph velocity and acceleration? | Anonymous Tue. 14, Feb 2012, 17:55 |

Please see link on the webpage for 1DMotion. There is a movie now showing you how to think about the PostLab. | Douglas Wed. 15, Feb 2012, 12:27 |

for the postlab question with the collision, do we use the equation we got for our own data? and wouldnt the acceleration graph for this one just be zero? | Anonymous Sat. 18, Feb 2012, 17:58 |

Use the PostLab only. All information is there. | Douglas Tue. 21, Feb 2012, 14:13 |

Hello, I am working on the postlab and I am having a hard time graphing the velocity and acceleration for the parabola given in the falling down graph. Would we have to do piecewise functions? | Anonymous Mon. 20, Feb 2012, 00:20 |

No, for an incline, the acceleration is constant (thus kinematics). | Douglas Tue. 21, Feb 2012, 14:13 |

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