IMPORTANT ANNOUNCEMENTS

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        SHM: SIMPLE HARMONIC MOTION


The Physics Departments of MSUDenver and UCDenver wish to thank you for your participation in our
Laboratory Program this semester.
Have a great break from school; and we hope to see you again.
FYI: Happy Face on Mars? See Below.
About the Happy Face

Happy Face on Mars???
https://mars.jpl.nasa.gov/mgs/msss/camera/images/3_11_99_happy/
https://www.msss.com/education/happy_face/happy_face.html

Thank You,

John Martinez
Physics Laboratory Manager
MSCD Physics,
in conjunction with UCDenver Physics;
Thus, MUSCD Physics.


Begin Q&A Forum for "SHM: SIMPLE HARMONIC MOTION"

Douglas-
In the post lab, question 8, is there any way that you could help me figure out what the spring constant value is or how to find it. What I took from the quation was to find the value for S, is that correct or are we supposed to find the value for K?
Anonymous
Wed. 29, Nov 2006, 22:11
F=-ks is Hooke's Law. If we plot F[N] vs. s[m] then the slope should be the spring constant k. There may also be a Forceoffset (systematic offset resulting from actual experimentation.) The negative sign just reminds us that the restoring force (F) is opposite the stretch direction.
y=mx+b translates to F = k s + Fo.
F is the brought on by the weight hanging from the spring; so we can say F = mg. k and Fo are given to us as m and b respectively.
I hope this helps a litte.
Douglas
Fri. 01, Dec 2006, 08:03

For question number 8, i don't know how to use the equation to find the spring constant in order to use it to get the answer. Anonymous
Thu. 30, Nov 2006, 17:37
F=-ks is Hooke's Law. If we plot F[N] vs. s[m] then the slope should be the spring constant k. There may also be a Forceoffset (systematic offset resulting from actual experimentation.) The negative sign just reminds us that the restoring force (F) is opposite the stretch direction.
y=mx+b translates to F = k s + Fo.
F is brought on by the weight hanging from the spring; so we can say
F = mg; where k and Fo are given to us as m and b respectively.
I hope this helps a litte.
Douglas
Fri. 01, Dec 2006, 08:05

It seems that on the question asking about the period of the SHM given by the graph, the answer should be 0.7s given that the object completes 10 cycles in 7 seconds. Am I wrong?Anonymous
Wed. 27, Apr 2011, 18:30
You have the right idea; and you are close to the correct value. I am guessing you guessed the time for ten cycles.

The SmartTool is turned on the in the graph and the tool is in Delta mode.
7.0612 [s] is the time found for the ten cycles.
Douglas
Thu. 28, Apr 2011, 07:47

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