
Douglas In the post lab, question 8, is there any way that you could help me figure out what the spring constant value is or how to find it. What I took from the quation was to find the value for S, is that correct or are we supposed to find the value for K?  Anonymous Wed. 29, Nov 2006, 22:11 
F=ks is Hooke's Law. If we plot F[N] vs. s[m] then the slope should be the spring constant k. There may also be a Force_{offset} (systematic offset resulting from actual experimentation.) The negative sign just reminds us that the restoring force (F) is opposite the stretch direction. y=mx+b translates to F = k s + F_{o}. F is the brought on by the weight hanging from the spring; so we can say F = mg. k and F_{o} are given to us as m and b respectively. I hope this helps a litte.  Douglas Fri. 01, Dec 2006, 08:03 
For question number 8, i don't know how to use the equation to find the spring constant in order to use it to get the answer.  Anonymous Thu. 30, Nov 2006, 17:37 
F=ks is Hooke's Law. If we plot F[N] vs. s[m] then the slope should be the spring constant k. There may also be a Force_{offset} (systematic offset resulting from actual experimentation.) The negative sign just reminds us that the restoring force (F) is opposite the stretch direction. y=mx+b translates to F = k s + F_{o}. F is brought on by the weight hanging from the spring; so we can say F = mg; where k and F_{o} are given to us as m and b respectively. I hope this helps a litte.  Douglas Fri. 01, Dec 2006, 08:05 
It seems that on the question asking about the period of the SHM given by the graph, the answer should be 0.7s given that the object completes 10 cycles in 7 seconds. Am I wrong?  Anonymous Wed. 27, Apr 2011, 18:30 
You have the right idea; and you are close to the correct value. I am guessing you guessed the time for ten cycles. The SmartTool is turned on the in the graph and the tool is in Delta mode. 7.0612 [s] is the time found for the ten cycles.  Douglas Thu. 28, Apr 2011, 07:47 